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14223433320022 = 27111716660011
BaseRepresentation
bin1100111011111010011010…
…1100001100011001010110
31212100202011112010122011111
43032332212230030121112
53331014042412220042
650130053254325234
72665415636262613
oct316764654143126
955322145118144
1014223433320022
114594140339a73
12171871b05981a
137c235803ba54
143725bc7d750a
15199eb6728517
hexcefa6b0c656

14223433320022 has 4 divisors (see below), whose sum is σ = 21335149980036. Its totient is φ = 7111716660010.

The previous prime is 14223433319983. The next prime is 14223433320059. The reversal of 14223433320022 is 22002333432241.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×142234333200223 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3555858330004 + ... + 3555858330007.

It is an arithmetic number, because the mean of its divisors is an integer number (5333787495009).

Almost surely, 214223433320022 is an apocalyptic number.

14223433320022 is a deficient number, since it is larger than the sum of its proper divisors (7111716660014).

14223433320022 is an equidigital number, since it uses as much as digits as its factorization.

14223433320022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7111716660013.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 14223433320022 its reverse (22002333432241), we get a palindrome (36225766752263).

The spelling of 14223433320022 in words is "fourteen trillion, two hundred twenty-three billion, four hundred thirty-three million, three hundred twenty thousand, twenty-two".

Divisors: 1 2 7111716660011 14223433320022