Base | Representation |
---|---|
bin | 100000010101110111011011… |
… | …111001001010000110001111 |
3 | 200122122000121121100221020021 |
4 | 200111313123321022012033 |
5 | 122120430232002314003 |
6 | 1222304113133203011 |
7 | 41650336541542516 |
oct | 4025673371120617 |
9 | 618560547327207 |
10 | 142240121135503 |
11 | 4135a773209156 |
12 | 13b53108930467 |
13 | 614a25547a1b1 |
14 | 271a65c55d67d |
15 | 1169ed2da22bd |
hex | 815ddbe4a18f |
142240121135503 has 16 divisors (see below), whose sum is σ = 142948540177920. Its totient is φ = 141533929028800.
The previous prime is 142240121135491. The next prime is 142240121135579. The reversal of 142240121135503 is 305531121042241.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142240121135503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142240121135303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 257939688 + ... + 258490546.
It is an arithmetic number, because the mean of its divisors is an integer number (8934283761120).
Almost surely, 2142240121135503 is an apocalyptic number.
142240121135503 is a deficient number, since it is larger than the sum of its proper divisors (708419042417).
142240121135503 is an equidigital number, since it uses as much as digits as its factorization.
142240121135503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 552878.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 142240121135503 its reverse (305531121042241), we get a palindrome (447771242177744).
The spelling of 142240121135503 in words is "one hundred forty-two trillion, two hundred forty billion, one hundred twenty-one million, one hundred thirty-five thousand, five hundred three".
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