14224100112113 has 2 divisors, whose sum is σ = 14224100112114. Its totient is φ = 14224100112112.

The previous prime is 14224100112097. The next prime is 14224100112121. The reversal of 14224100112113 is 31121100142241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13281119282929 + 942980829184 = 3644327^2 + 971072^2 .

It is an emirp because it is prime and its reverse (31121100142241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14224100112113 - 2⁴ = 14224100112097 is a prime.

It is not a weakly prime, because it can be changed into another prime (14224100112143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112050056056 + 7112050056057.

It is an arithmetic number, because the mean of its divisors is an integer number (7112050056057).

Almost surely, 2^{14224100112113} is an apocalyptic number.

It is an amenable number.

14224100112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14224100112113 is an equidigital number, since it uses as much as digits as its factorization.

14224100112113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 14224100112113 its reverse (31121100142241), we get a palindrome (45345200254354).

The spelling of 14224100112113 in words is "fourteen trillion, two hundred twenty-four billion, one hundred million, one hundred twelve thousand, one hundred thirteen".