Base | Representation |
---|---|
bin | 1100111011111101010011… |
… | …1111011111110100010011 |
3 | 1212100211011122211210012111 |
4 | 3032333110333133310103 |
5 | 3331022140243212433 |
6 | 50130302324210151 |
7 | 2665444121132356 |
oct | 316772477376423 |
9 | 55324148753174 |
10 | 14224210132243 |
11 | 45944a9882541 |
12 | 17188b7239957 |
13 | 7c244cc63557 |
14 | 372653a4829d |
15 | 19a00ea1edcd |
hex | cefd4fdfd13 |
14224210132243 has 2 divisors, whose sum is σ = 14224210132244. Its totient is φ = 14224210132242.
The previous prime is 14224210132229. The next prime is 14224210132261. The reversal of 14224210132243 is 34223101242241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14224210132243 - 221 = 14224208035091 is a prime.
It is a super-2 number, since 2×142242101322432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14224210132273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112105066121 + 7112105066122.
It is an arithmetic number, because the mean of its divisors is an integer number (7112105066122).
Almost surely, 214224210132243 is an apocalyptic number.
14224210132243 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224210132243 is an equidigital number, since it uses as much as digits as its factorization.
14224210132243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 14224210132243 its reverse (34223101242241), we get a palindrome (48447311374484).
The spelling of 14224210132243 in words is "fourteen trillion, two hundred twenty-four billion, two hundred ten million, one hundred thirty-two thousand, two hundred forty-three".
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