Base | Representation |
---|---|
bin | 10100101100101111000… |
… | …001100111111111111111 |
3 | 12000222112010001211100021 |
4 | 110230233001213333333 |
5 | 141301110310130421 |
6 | 3005241400113011 |
7 | 204523654054144 |
oct | 24545701477777 |
9 | 5028463054307 |
10 | 1422423130111 |
11 | 4a9278857885 |
12 | 1ab812765767 |
13 | a41983084b9 |
14 | 4cbba6523cb |
15 | 270019c0341 |
hex | 14b2f067fff |
1422423130111 has 16 divisors (see below), whose sum is σ = 1533513421440. Its totient is φ = 1315012920480.
The previous prime is 1422423130087. The next prime is 1422423130147. The reversal of 1422423130111 is 1110313242241.
It is a cyclic number.
It is not a de Polignac number, because 1422423130111 - 213 = 1422423121919 is a prime.
It is a super-2 number, since 2×14224231301112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1422423130211) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 93441 + ... + 1689253.
It is an arithmetic number, because the mean of its divisors is an integer number (95844588840).
Almost surely, 21422423130111 is an apocalyptic number.
1422423130111 is a deficient number, since it is larger than the sum of its proper divisors (111090291329).
1422423130111 is a wasteful number, since it uses less digits than its factorization.
1422423130111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1596966.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1422423130111 its reverse (1110313242241), we get a palindrome (2532736372352).
The spelling of 1422423130111 in words is "one trillion, four hundred twenty-two billion, four hundred twenty-three million, one hundred thirty thousand, one hundred eleven".
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