Base | Representation |
---|---|
bin | 11010011111110000… |
… | …00101101100010111 |
3 | 1100201100212010212110 |
4 | 31033320011230113 |
5 | 213113100132320 |
6 | 10311311122103 |
7 | 1012336356522 |
oct | 151770055427 |
9 | 40640763773 |
10 | 14225005335 |
11 | 603a710062 |
12 | 290bb13333 |
13 | 145910c928 |
14 | 98d327bb9 |
15 | 583c7b5e0 |
hex | 34fe05b17 |
14225005335 has 8 divisors (see below), whose sum is σ = 22760008560. Its totient is φ = 7586669504.
The previous prime is 14225005313. The next prime is 14225005393. The reversal of 14225005335 is 53350052241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14225005335 - 26 = 14225005271 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 474166830 + ... + 474166859.
It is an arithmetic number, because the mean of its divisors is an integer number (2845001070).
Almost surely, 214225005335 is an apocalyptic number.
14225005335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14225005335 is a deficient number, since it is larger than the sum of its proper divisors (8535003225).
14225005335 is an equidigital number, since it uses as much as digits as its factorization.
14225005335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 948333697.
The product of its (nonzero) digits is 18000, while the sum is 30.
Adding to 14225005335 its reverse (53350052241), we get a palindrome (67575057576).
The spelling of 14225005335 in words is "fourteen billion, two hundred twenty-five million, five thousand, three hundred thirty-five".
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