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142255235011 is a prime number
BaseRepresentation
bin1000010001111100010…
…0101001111111000011
3111121012000022200120211
42010133010221333003
54312314320010021
6145203503214551
713164134355331
oct2043704517703
9447160280524
10142255235011
115536a40a62a
12236a0ba7457
1310550b92796
146c56d66b51
153a78bee3e1
hex211f129fc3

142255235011 has 2 divisors, whose sum is σ = 142255235012. Its totient is φ = 142255235010.

The previous prime is 142255234993. The next prime is 142255235041. The reversal of 142255235011 is 110532552241.

142255235011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (110532552241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142255235011 is a prime.

It is a super-3 number, since 3×1422552350113 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (142255235041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71127617505 + 71127617506.

It is an arithmetic number, because the mean of its divisors is an integer number (71127617506).

Almost surely, 2142255235011 is an apocalyptic number.

142255235011 is a deficient number, since it is larger than the sum of its proper divisors (1).

142255235011 is an equidigital number, since it uses as much as digits as its factorization.

142255235011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 142255235011 its reverse (110532552241), we get a palindrome (252787787252).

The spelling of 142255235011 in words is "one hundred forty-two billion, two hundred fifty-five million, two hundred thirty-five thousand, eleven".