Base | Representation |
---|---|
bin | 100000010110100110110100… |
… | …010110001100011110110110 |
3 | 200122210212221020210011110001 |
4 | 200112212310112030132312 |
5 | 122122243430300010413 |
6 | 1222343325353221514 |
7 | 41654120362531603 |
oct | 4026466426143666 |
9 | 618725836704401 |
10 | 142290997266358 |
11 | 4137a300490296 |
12 | 13b60b4710189a |
13 | 6151ca28a7035 |
14 | 271ccc73956aa |
15 | 116b4ae60b4dd |
hex | 8169b458c7b6 |
142290997266358 has 4 divisors (see below), whose sum is σ = 213436495899540. Its totient is φ = 71145498633178.
The previous prime is 142290997266317. The next prime is 142290997266463. The reversal of 142290997266358 is 853662799092241.
142290997266358 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35572749316588 + ... + 35572749316591.
It is an arithmetic number, because the mean of its divisors is an integer number (53359123974885).
It is a 1-persistent number, because it is pandigital, but 2⋅142290997266358 = 284581994532716 is not.
Almost surely, 2142290997266358 is an apocalyptic number.
142290997266358 is a deficient number, since it is larger than the sum of its proper divisors (71145498633182).
142290997266358 is an equidigital number, since it uses as much as digits as its factorization.
142290997266358 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71145498633181.
The product of its (nonzero) digits is 705438720, while the sum is 73.
The spelling of 142290997266358 in words is "one hundred forty-two trillion, two hundred ninety billion, nine hundred ninety-seven million, two hundred sixty-six thousand, three hundred fifty-eight".
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