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142310561986057 is a prime number
BaseRepresentation
bin100000010110111001000010…
…011111101011011000001001
3200122212202102202020220101011
4200112321002133223120021
5122123104012332023212
61222400323013123521
741655412251103663
oct4026710237533011
9618782382226334
10142310561986057
1141387630237823
1213b648a73295a1
136153aa0039b5a
14271dc21931533
15116bc570454a7
hex816e427eb609

142310561986057 has 2 divisors, whose sum is σ = 142310561986058. Its totient is φ = 142310561986056.

The previous prime is 142310561985901. The next prime is 142310561986067. The reversal of 142310561986057 is 750689165013241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 141434196397321 + 876365588736 = 11892611^2 + 936144^2 .

It is a cyclic number.

It is not a de Polignac number, because 142310561986057 - 243 = 133514468963849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142310561985992 and 142310561986010.

It is not a weakly prime, because it can be changed into another prime (142310561986067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71155280993028 + 71155280993029.

It is an arithmetic number, because the mean of its divisors is an integer number (71155280993029).

It is a 1-persistent number, because it is pandigital, but 2⋅142310561986057 = 284621123972114 is not.

Almost surely, 2142310561986057 is an apocalyptic number.

It is an amenable number.

142310561986057 is a deficient number, since it is larger than the sum of its proper divisors (1).

142310561986057 is an equidigital number, since it uses as much as digits as its factorization.

142310561986057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10886400, while the sum is 58.

The spelling of 142310561986057 in words is "one hundred forty-two trillion, three hundred ten billion, five hundred sixty-one million, nine hundred eighty-six thousand, fifty-seven".