Base | Representation |
---|---|
bin | 1100111100010111010110… |
… | …1000011110010010101001 |
3 | 1212101111012210212210200121 |
4 | 3033011311220132102221 |
5 | 3331130444222231003 |
6 | 50133420105403241 |
7 | 2666112256525312 |
oct | 317056550362251 |
9 | 55344183783617 |
10 | 14231200195753 |
11 | 459746655a732 |
12 | 171a128199521 |
13 | 7c2cc519a7c8 |
14 | 372b18139609 |
15 | 19a2bd524cbd |
hex | cf175a1e4a9 |
14231200195753 has 2 divisors, whose sum is σ = 14231200195754. Its totient is φ = 14231200195752.
The previous prime is 14231200195721. The next prime is 14231200195763. The reversal of 14231200195753 is 35759100213241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13756109819929 + 475090375824 = 3708923^2 + 689268^2 .
It is a cyclic number.
It is not a de Polignac number, because 14231200195753 - 25 = 14231200195721 is a prime.
It is not a weakly prime, because it can be changed into another prime (14231200195763) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115600097876 + 7115600097877.
It is an arithmetic number, because the mean of its divisors is an integer number (7115600097877).
Almost surely, 214231200195753 is an apocalyptic number.
It is an amenable number.
14231200195753 is a deficient number, since it is larger than the sum of its proper divisors (1).
14231200195753 is an equidigital number, since it uses as much as digits as its factorization.
14231200195753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 226800, while the sum is 43.
The spelling of 14231200195753 in words is "fourteen trillion, two hundred thirty-one billion, two hundred million, one hundred ninety-five thousand, seven hundred fifty-three".
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