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14231311331 is a prime number
BaseRepresentation
bin11010100000100000…
…01001001111100011
31100201210201112001212
431100100021033203
5213121203430311
610312054220335
71012444102406
oct152020111743
940653645055
1014231311331
116043227926
1229120546ab
13145a509ca3
149900c9d3d
155845c4c8b
hex3504093e3

14231311331 has 2 divisors, whose sum is σ = 14231311332. Its totient is φ = 14231311330.

The previous prime is 14231311327. The next prime is 14231311343. The reversal of 14231311331 is 13311313241.

It is a weak prime.

It is an emirp because it is prime and its reverse (13311313241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14231311331 - 22 = 14231311327 is a prime.

It is a super-2 number, since 2×142313113312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14231311297 and 14231311306.

It is not a weakly prime, because it can be changed into another prime (14231311631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115655665 + 7115655666.

It is an arithmetic number, because the mean of its divisors is an integer number (7115655666).

Almost surely, 214231311331 is an apocalyptic number.

14231311331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14231311331 is an equidigital number, since it uses as much as digits as its factorization.

14231311331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 648, while the sum is 23.

Adding to 14231311331 its reverse (13311313241), we get a palindrome (27542624572).

The spelling of 14231311331 in words is "fourteen billion, two hundred thirty-one million, three hundred eleven thousand, three hundred thirty-one".