1423201004341 has 4 divisors (see below), whose sum is σ = 1425354107884. Its totient is φ = 1421047900800.

The previous prime is 1423201004317. The next prime is 1423201004377. The reversal of 1423201004341 is 1434001023241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 488711448241 + 934489556100 = 699079^2 + 966690^2 .

It is a cyclic number.

It is not a de Polignac number, because 1423201004341 - 2¹⁵ = 1423200971573 is a prime.

It is a super-2 number, since 2×1423201004341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1423201004311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1076550780 + ... + 1076552101.

It is an arithmetic number, because the mean of its divisors is an integer number (356338526971).

Almost surely, 2^{1423201004341} is an apocalyptic number.

It is an amenable number.

1423201004341 is a deficient number, since it is larger than the sum of its proper divisors (2153103543).

1423201004341 is an equidigital number, since it uses as much as digits as its factorization.

1423201004341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2153103542.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1423201004341 its reverse (1434001023241), we get a palindrome (2857202027582).

The spelling of 1423201004341 in words is "one trillion, four hundred twenty-three billion, two hundred one million, four thousand, three hundred forty-one".