Base | Representation |
---|---|
bin | 100000010111000101000111… |
… | …101000001111111101010011 |
3 | 200122220222220201112202021011 |
4 | 200113011013220033331103 |
5 | 122123312043423133021 |
6 | 1222410310051311351 |
7 | 41656351553063266 |
oct | 4027050750177523 |
9 | 618828821482234 |
10 | 142323533021011 |
11 | 41392087029321 |
12 | 13b673072ab557 |
13 | 6155089409974 |
14 | 27206d24bacdd |
15 | 116c265b74de1 |
hex | 817147a0ff53 |
142323533021011 has 2 divisors, whose sum is σ = 142323533021012. Its totient is φ = 142323533021010.
The previous prime is 142323533020993. The next prime is 142323533021099. The reversal of 142323533021011 is 110120335323241.
142323533021011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142323533021011 is a prime.
It is not a weakly prime, because it can be changed into another prime (142323533024011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71161766510505 + 71161766510506.
It is an arithmetic number, because the mean of its divisors is an integer number (71161766510506).
Almost surely, 2142323533021011 is an apocalyptic number.
142323533021011 is a deficient number, since it is larger than the sum of its proper divisors (1).
142323533021011 is an equidigital number, since it uses as much as digits as its factorization.
142323533021011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 142323533021011 its reverse (110120335323241), we get a palindrome (252443868344252).
The spelling of 142323533021011 in words is "one hundred forty-two trillion, three hundred twenty-three billion, five hundred thirty-three million, twenty-one thousand, eleven".
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