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142324011251027 is a prime number
BaseRepresentation
bin100000010111000101100100…
…001000100011010101010011
3200122221001011001102100111222
4200113011210020203111103
5122123314033340013102
61222410425333355255
741656366451010014
oct4027054410432523
9618831131370458
10142324011251027
1141392301a76641
1213b6741b498b2b
13615513450bac8
142720739c0700b
15116c292b3caa2
hex817164223553

142324011251027 has 2 divisors, whose sum is σ = 142324011251028. Its totient is φ = 142324011251026.

The previous prime is 142324011250931. The next prime is 142324011251069. The reversal of 142324011251027 is 720152110423241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142324011251027 - 236 = 142255291774291 is a prime.

It is a super-2 number, since 2×1423240112510272 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (142324011251077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71162005625513 + 71162005625514.

It is an arithmetic number, because the mean of its divisors is an integer number (71162005625514).

Almost surely, 2142324011251027 is an apocalyptic number.

142324011251027 is a deficient number, since it is larger than the sum of its proper divisors (1).

142324011251027 is an equidigital number, since it uses as much as digits as its factorization.

142324011251027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26880, while the sum is 35.

Adding to 142324011251027 its reverse (720152110423241), we get a palindrome (862476121674268).

The spelling of 142324011251027 in words is "one hundred forty-two trillion, three hundred twenty-four billion, eleven million, two hundred fifty-one thousand, twenty-seven".