Base | Representation |
---|---|
bin | 1100111100011110001001… |
… | …0111011010101010101001 |
3 | 1212101122220221112001201102 |
4 | 3033013202113122222221 |
5 | 3331143213224103001 |
6 | 50134321113331145 |
7 | 2666205420412502 |
oct | 317074227325251 |
9 | 55348827461642 |
10 | 14233024441001 |
11 | 4598212274133 |
12 | 171a557106ab5 |
13 | 7c32260c9372 |
14 | 372c4c523ba9 |
15 | 19a37876be6b |
hex | cf1e25daaa9 |
14233024441001 has 2 divisors, whose sum is σ = 14233024441002. Its totient is φ = 14233024441000.
The previous prime is 14233024440983. The next prime is 14233024441043. The reversal of 14233024441001 is 10014442033241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13694062901401 + 538961539600 = 3700549^2 + 734140^2 .
It is a cyclic number.
It is not a de Polignac number, because 14233024441001 - 214 = 14233024424617 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (14233024441091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7116512220500 + 7116512220501.
It is an arithmetic number, because the mean of its divisors is an integer number (7116512220501).
Almost surely, 214233024441001 is an apocalyptic number.
It is an amenable number.
14233024441001 is a deficient number, since it is larger than the sum of its proper divisors (1).
14233024441001 is an equidigital number, since it uses as much as digits as its factorization.
14233024441001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 14233024441001 its reverse (10014442033241), we get a palindrome (24247466474242).
The spelling of 14233024441001 in words is "fourteen trillion, two hundred thirty-three billion, twenty-four million, four hundred forty-one thousand, one".
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