Base | Representation |
---|---|
bin | 100000010111001101000001… |
… | …001000101101101110001011 |
3 | 200122221210210210001102102122 |
4 | 200113031001020231232023 |
5 | 122123431431042304421 |
6 | 1222414231412521455 |
7 | 41660101664324234 |
oct | 4027150110555613 |
9 | 618853723042378 |
10 | 142332014025611 |
11 | 41395739369633 |
12 | 13b68a9362028b |
13 | 6155b0b4b3a97 |
14 | 2720c989d408b |
15 | 116c5b04d52ab |
hex | 81734122db8b |
142332014025611 has 2 divisors, whose sum is σ = 142332014025612. Its totient is φ = 142332014025610.
The previous prime is 142332014025527. The next prime is 142332014025653. The reversal of 142332014025611 is 116520410233241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142332014025611 is a prime.
It is not a weakly prime, because it can be changed into another prime (142332014025011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71166007012805 + 71166007012806.
It is an arithmetic number, because the mean of its divisors is an integer number (71166007012806).
Almost surely, 2142332014025611 is an apocalyptic number.
142332014025611 is a deficient number, since it is larger than the sum of its proper divisors (1).
142332014025611 is an equidigital number, since it uses as much as digits as its factorization.
142332014025611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 35.
Adding to 142332014025611 its reverse (116520410233241), we get a palindrome (258852424258852).
The spelling of 142332014025611 in words is "one hundred forty-two trillion, three hundred thirty-two billion, fourteen million, twenty-five thousand, six hundred eleven".
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