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14233311121 is a prime number
BaseRepresentation
bin11010100000101111…
…10001011110010001
31100201221111010021011
431100113301132101
5213122211423441
610312205130521
71012500101611
oct152027613621
940657433234
1014233311121
116044373347
122912859a41
13145aa5a2b3
1499048aa41
1558486c581
hex3505f1791

14233311121 has 2 divisors, whose sum is σ = 14233311122. Its totient is φ = 14233311120.

The previous prime is 14233311031. The next prime is 14233311151. The reversal of 14233311121 is 12111333241.

14233311121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13776890625 + 456420496 = 117375^2 + 21364^2 .

It is a cyclic number.

It is not a de Polignac number, because 14233311121 - 229 = 13696440209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14233311092 and 14233311101.

It is not a weakly prime, because it can be changed into another prime (14233311151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7116655560 + 7116655561.

It is an arithmetic number, because the mean of its divisors is an integer number (7116655561).

Almost surely, 214233311121 is an apocalyptic number.

It is an amenable number.

14233311121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14233311121 is an equidigital number, since it uses as much as digits as its factorization.

14233311121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432, while the sum is 22.

Adding to 14233311121 its reverse (12111333241), we get a palindrome (26344644362).

The spelling of 14233311121 in words is "fourteen billion, two hundred thirty-three million, three hundred eleven thousand, one hundred twenty-one".