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142340003233121 is a prime number
BaseRepresentation
bin100000010111010100011101…
…010101000111110101100001
3200122222120102120011012211002
4200113110131111013311201
5122124044311311424441
61222422032245201345
741660503654424351
oct4027243525076541
9618876376135732
10142340003233121
1141399069035471
1213b6a543100255
1361567b27186c5
142721415a8cb61
15116c8cba9cb9b
hex81751d547d61

142340003233121 has 2 divisors, whose sum is σ = 142340003233122. Its totient is φ = 142340003233120.

The previous prime is 142340003233091. The next prime is 142340003233139. The reversal of 142340003233121 is 121332300043241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121170802233121 + 21169201000000 = 11007761^2 + 4601000^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142340003233121 is a prime.

It is not a weakly prime, because it can be changed into another prime (142340003232121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71170001616560 + 71170001616561.

It is an arithmetic number, because the mean of its divisors is an integer number (71170001616561).

Almost surely, 2142340003233121 is an apocalyptic number.

It is an amenable number.

142340003233121 is a deficient number, since it is larger than the sum of its proper divisors (1).

142340003233121 is an equidigital number, since it uses as much as digits as its factorization.

142340003233121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 142340003233121 its reverse (121332300043241), we get a palindrome (263672303276362).

The spelling of 142340003233121 in words is "one hundred forty-two trillion, three hundred forty billion, three million, two hundred thirty-three thousand, one hundred twenty-one".