Base | Representation |
---|---|
bin | 10100101101101001100… |
… | …011001111111110101111 |
3 | 12001002001112200011101011 |
4 | 110231221203033332233 |
5 | 141310113141220101 |
6 | 3005523033330051 |
7 | 204560206032106 |
oct | 24555143177657 |
9 | 5032045604334 |
10 | 1423405023151 |
11 | 4a9732033631 |
12 | 1aba47566927 |
13 | a42c3875ab7 |
14 | 4cc70c0903d |
15 | 2705ccc6751 |
hex | 14b698cffaf |
1423405023151 has 4 divisors (see below), whose sum is σ = 1424744069392. Its totient is φ = 1422065976912.
The previous prime is 1423405023113. The next prime is 1423405023193. The reversal of 1423405023151 is 1513205043241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1423405023151 - 215 = 1423404990383 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1423405021151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 669521526 + ... + 669523651.
It is an arithmetic number, because the mean of its divisors is an integer number (356186017348).
Almost surely, 21423405023151 is an apocalyptic number.
1423405023151 is a deficient number, since it is larger than the sum of its proper divisors (1339046241).
1423405023151 is a wasteful number, since it uses less digits than its factorization.
1423405023151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1339046240.
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 1423405023151 in words is "one trillion, four hundred twenty-three billion, four hundred five million, twenty-three thousand, one hundred fifty-one".
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