Base | Representation |
---|---|
bin | 10100101101101001100… |
… | …011001111111111011001 |
3 | 12001002001112200011102201 |
4 | 110231221203033333121 |
5 | 141310113141220233 |
6 | 3005523033330201 |
7 | 204560206032166 |
oct | 24555143177731 |
9 | 5032045604381 |
10 | 1423405023193 |
11 | 4a973203366a |
12 | 1aba47566961 |
13 | a42c3875b1a |
14 | 4cc70c0906d |
15 | 2705ccc677d |
hex | 14b698cffd9 |
1423405023193 has 2 divisors, whose sum is σ = 1423405023194. Its totient is φ = 1423405023192.
The previous prime is 1423405023113. The next prime is 1423405023239. The reversal of 1423405023193 is 3913205043241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1415155297609 + 8249725584 = 1189603^2 + 90828^2 .
It is a cyclic number.
It is not a de Polignac number, because 1423405023193 - 233 = 1414815088601 is a prime.
It is not a weakly prime, because it can be changed into another prime (1423405023113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711702511596 + 711702511597.
It is an arithmetic number, because the mean of its divisors is an integer number (711702511597).
Almost surely, 21423405023193 is an apocalyptic number.
It is an amenable number.
1423405023193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1423405023193 is an equidigital number, since it uses as much as digits as its factorization.
1423405023193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 37.
The spelling of 1423405023193 in words is "one trillion, four hundred twenty-three billion, four hundred five million, twenty-three thousand, one hundred ninety-three".
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