Base | Representation |
---|---|
bin | 1000010010010000110… |
… | …0101000010000001011 |
3 | 111121102000002201200011 |
4 | 2010210030220100023 |
5 | 4313003322224042 |
6 | 145220214052351 |
7 | 13166230221532 |
oct | 2044414502013 |
9 | 447360081604 |
10 | 142341211147 |
11 | 554039a2793 |
12 | 2370594a0b7 |
13 | 10565936035 |
14 | 6c64547319 |
15 | 3a81533a17 |
hex | 212432840b |
142341211147 has 2 divisors, whose sum is σ = 142341211148. Its totient is φ = 142341211146.
The previous prime is 142341211087. The next prime is 142341211169. The reversal of 142341211147 is 741112143241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142341211147 - 215 = 142341178379 is a prime.
It is a super-2 number, since 2×1423412111472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142341211447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71170605573 + 71170605574.
It is an arithmetic number, because the mean of its divisors is an integer number (71170605574).
Almost surely, 2142341211147 is an apocalyptic number.
142341211147 is a deficient number, since it is larger than the sum of its proper divisors (1).
142341211147 is an equidigital number, since it uses as much as digits as its factorization.
142341211147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5376, while the sum is 31.
Adding to 142341211147 its reverse (741112143241), we get a palindrome (883453354388).
The spelling of 142341211147 in words is "one hundred forty-two billion, three hundred forty-one million, two hundred eleven thousand, one hundred forty-seven".
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