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14234123113 = 74094971751
BaseRepresentation
bin11010100000110101…
…10111101101101001
31100202000000101002221
431100122313231221
5213122413414423
610312234354041
71012510023130
oct152032675551
940660011087
1014234123113
116044878411
122912b8b921
13145ac82a72
1499061c917
1558497ce5d
hex3506b7b69

14234123113 has 8 divisors (see below), whose sum is σ = 16307346560. Its totient is φ = 12170844000.

The previous prime is 14234123003. The next prime is 14234123129. The reversal of 14234123113 is 31132143241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14234123113 - 229 = 13697252201 is a prime.

It is a super-2 number, since 2×142341231132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14234127113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2483013 + ... + 2488738.

It is an arithmetic number, because the mean of its divisors is an integer number (2038418320).

Almost surely, 214234123113 is an apocalyptic number.

It is an amenable number.

14234123113 is a deficient number, since it is larger than the sum of its proper divisors (2073223447).

14234123113 is an equidigital number, since it uses as much as digits as its factorization.

14234123113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4972167.

The product of its digits is 1728, while the sum is 25.

Adding to 14234123113 its reverse (31132143241), we get a palindrome (45366266354).

The spelling of 14234123113 in words is "fourteen billion, two hundred thirty-four million, one hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 7 409 2863 4971751 34802257 2033446159 14234123113