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14234134503 = 35980418839
BaseRepresentation
bin11010100000110101…
…11010011111100111
31100202000000221201210
431100122322133213
5213122414301003
610312234522503
71012510101261
oct152032723747
940660027653
1014234134503
116044885a26
122912b96433
13145ac87cc4
14990622b31
15584981503
hex3506ba7e7

14234134503 has 8 divisors (see below), whose sum is σ = 19300521600. Its totient is φ = 9328585208.

The previous prime is 14234134501. The next prime is 14234134529. The reversal of 14234134503 is 30543143241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14234134503 - 21 = 14234134501 is a prime.

It is a super-2 number, since 2×142341345032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14234134501) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40209243 + ... + 40209596.

It is an arithmetic number, because the mean of its divisors is an integer number (2412565200).

Almost surely, 214234134503 is an apocalyptic number.

14234134503 is a deficient number, since it is larger than the sum of its proper divisors (5066387097).

14234134503 is an equidigital number, since it uses as much as digits as its factorization.

14234134503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80418901.

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 14234134503 its reverse (30543143241), we get a palindrome (44777277744).

The spelling of 14234134503 in words is "fourteen billion, two hundred thirty-four million, one hundred thirty-four thousand, five hundred three".

Divisors: 1 3 59 177 80418839 241256517 4744711501 14234134503