Base | Representation |
---|---|
bin | 1100111100100010101001… |
… | …1110010100101111100111 |
3 | 1212101210001020220202120220 |
4 | 3033020222132110233213 |
5 | 3331203202424230203 |
6 | 50135041131055423 |
7 | 2666250410322561 |
oct | 317105236245747 |
9 | 55353036822526 |
10 | 14234234211303 |
11 | 45987831434a7 |
12 | 171a8342a1573 |
13 | 7c3389931992 |
14 | 372d25078331 |
15 | 19a3e9a87653 |
hex | cf22a794be7 |
14234234211303 has 16 divisors (see below), whose sum is σ = 19489874267136. Its totient is φ = 9236272799520.
The previous prime is 14234234211229. The next prime is 14234234211347. The reversal of 14234234211303 is 30311243243241.
It is a de Polignac number, because none of the positive numbers 2k-14234234211303 is a prime.
It is a super-2 number, since 2×142342342113032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14234234210303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 278847451 + ... + 278898492.
It is an arithmetic number, because the mean of its divisors is an integer number (1218117141696).
Almost surely, 214234234211303 is an apocalyptic number.
14234234211303 is a deficient number, since it is larger than the sum of its proper divisors (5255640055833).
14234234211303 is a wasteful number, since it uses less digits than its factorization.
14234234211303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 557746174.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 14234234211303 its reverse (30311243243241), we get a palindrome (44545477454544).
The spelling of 14234234211303 in words is "fourteen trillion, two hundred thirty-four billion, two hundred thirty-four million, two hundred eleven thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •