14234340120001 has 4 divisors (see below), whose sum is σ = 14381085894532. Its totient is φ = 14087594345472.

The previous prime is 14234340119981. The next prime is 14234340120089. The reversal of 14234340120001 is 10002104343241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3927832479376 + 10306507640625 = 1981876^2 + 3210375^2 .

It is a cyclic number.

It is not a de Polignac number, because 14234340120001 - 2¹³ = 14234340111809 is a prime.

It is a super-3 number, since 3×14234340120001³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14234340123001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73372887120 + ... + 73372887313.

It is an arithmetic number, because the mean of its divisors is an integer number (3595271473633).

Almost surely, 2^{14234340120001} is an apocalyptic number.

It is an amenable number.

14234340120001 is a deficient number, since it is larger than the sum of its proper divisors (146745774531).

14234340120001 is an equidigital number, since it uses as much as digits as its factorization.

14234340120001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146745774530.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14234340120001 its reverse (10002104343241), we get a palindrome (24236444463242).

The spelling of 14234340120001 in words is "fourteen trillion, two hundred thirty-four billion, three hundred forty million, one hundred twenty thousand, one".