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142350130042 = 271175065021
BaseRepresentation
bin1000010010010010111…
…0101001101101111010
3111121102121212212002121
42010210232221231322
54313013113130132
6145221133151454
713166366066251
oct2044456515572
9447377785077
10142350130042
1155408a3467a
122370892b58a
13105677397a3
146c657c9798
153a821e6497
hex2124ba9b7a

142350130042 has 4 divisors (see below), whose sum is σ = 213525195066. Its totient is φ = 71175065020.

The previous prime is 142350130009. The next prime is 142350130073. The reversal of 142350130042 is 240031053241.

142350130042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 92683104721 + 49667025321 = 304439^2 + 222861^2 .

It is a junction number, because it is equal to n+sod(n) for n = 142350129989 and 142350130016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35587532509 + ... + 35587532512.

Almost surely, 2142350130042 is an apocalyptic number.

142350130042 is a deficient number, since it is larger than the sum of its proper divisors (71175065024).

142350130042 is an equidigital number, since it uses as much as digits as its factorization.

142350130042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71175065023.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 142350130042 its reverse (240031053241), we get a palindrome (382381183283).

The spelling of 142350130042 in words is "one hundred forty-two billion, three hundred fifty million, one hundred thirty thousand, forty-two".

Divisors: 1 2 71175065021 142350130042