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142354555041619 is a prime number
BaseRepresentation
bin100000010111100010000000…
…101011110111011101010011
3200200000221222200221200100101
4200113202000223313131103
5122124314112042312434
61222432440233033231
741661530402646124
oct4027420053673523
9620027880850311
10142354555041619
11413a4256166588
1213b71324555817
136157c9144bc8b
142721dd656604b
15116ce7e37eb14
hex817880af7753

142354555041619 has 2 divisors, whose sum is σ = 142354555041620. Its totient is φ = 142354555041618.

The previous prime is 142354555041557. The next prime is 142354555041659. The reversal of 142354555041619 is 916140555453241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142354555041619 - 245 = 107170182952787 is a prime.

It is a super-3 number, since 3×1423545550416193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 142354555041619.

It is not a weakly prime, because it can be changed into another prime (142354555041659) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71177277520809 + 71177277520810.

It is an arithmetic number, because the mean of its divisors is an integer number (71177277520810).

Almost surely, 2142354555041619 is an apocalyptic number.

142354555041619 is a deficient number, since it is larger than the sum of its proper divisors (1).

142354555041619 is an equidigital number, since it uses as much as digits as its factorization.

142354555041619 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960000, while the sum is 55.

The spelling of 142354555041619 in words is "one hundred forty-two trillion, three hundred fifty-four billion, five hundred fifty-five million, forty-one thousand, six hundred nineteen".