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14238097673 is a prime number
BaseRepresentation
bin11010100001010100…
…00010000100001001
31100202021111022011212
431100222002010021
5213124423111143
610312455502505
71012555555562
oct152052020411
940667438155
1014238097673
116047042578
122914387a35
13145ba44b87
14990d75169
15584eb5918
hex350a82109

14238097673 has 2 divisors, whose sum is σ = 14238097674. Its totient is φ = 14238097672.

The previous prime is 14238097637. The next prime is 14238097691. The reversal of 14238097673 is 37679083241.

Together with previous prime (14238097637) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11883616144 + 2354481529 = 109012^2 + 48523^2 .

It is an emirp because it is prime and its reverse (37679083241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14238097673 - 214 = 14238081289 is a prime.

It is not a weakly prime, because it can be changed into another prime (14238097273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7119048836 + 7119048837.

It is an arithmetic number, because the mean of its divisors is an integer number (7119048837).

Almost surely, 214238097673 is an apocalyptic number.

It is an amenable number.

14238097673 is a deficient number, since it is larger than the sum of its proper divisors (1).

14238097673 is an equidigital number, since it uses as much as digits as its factorization.

14238097673 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1524096, while the sum is 50.

The spelling of 14238097673 in words is "fourteen billion, two hundred thirty-eight million, ninety-seven thousand, six hundred seventy-three".