Base | Representation |
---|---|
bin | 1000010010011110110… |
… | …1010001100001010001 |
3 | 111121120002220121120211 |
4 | 2010213231101201101 |
5 | 4313113411203213 |
6 | 145230120204121 |
7 | 13200543611443 |
oct | 2044755214121 |
9 | 447502817524 |
10 | 142400100433 |
11 | 55434165118 |
12 | 23721609641 |
13 | 10574bb4576 |
14 | 6c6c2b6493 |
15 | 3a867b753d |
hex | 2127b51851 |
142400100433 has 2 divisors, whose sum is σ = 142400100434. Its totient is φ = 142400100432.
The previous prime is 142400100397. The next prime is 142400100467. The reversal of 142400100433 is 334001004241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 141321109329 + 1078991104 = 375927^2 + 32848^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142400100433 is a prime.
It is not a weakly prime, because it can be changed into another prime (142400109433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71200050216 + 71200050217.
It is an arithmetic number, because the mean of its divisors is an integer number (71200050217).
Almost surely, 2142400100433 is an apocalyptic number.
It is an amenable number.
142400100433 is a deficient number, since it is larger than the sum of its proper divisors (1).
142400100433 is an equidigital number, since it uses as much as digits as its factorization.
142400100433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 142400100433 its reverse (334001004241), we get a palindrome (476401104674).
The spelling of 142400100433 in words is "one hundred forty-two billion, four hundred million, one hundred thousand, four hundred thirty-three".
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