Base | Representation |
---|---|
bin | 1100111100111000001010… |
… | …1111100110001000111111 |
3 | 1212102022221210021101011001 |
4 | 3033032002233212020333 |
5 | 3331302020041220221 |
6 | 50141434220311131 |
7 | 2666543503506211 |
oct | 317160257461077 |
9 | 55368853241131 |
10 | 14240010101311 |
11 | 45a0177514115 |
12 | 171b9866a24a7 |
13 | 7c3a9a451387 |
14 | 3733121ca5b1 |
15 | 19a636ba2391 |
hex | cf382be623f |
14240010101311 has 4 divisors (see below), whose sum is σ = 14240295310752. Its totient is φ = 14239724891872.
The previous prime is 14240010101299. The next prime is 14240010101347. The reversal of 14240010101311 is 11310101004241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14240010101311 - 25 = 14240010101279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14240010101351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142529815 + ... + 142629688.
It is an arithmetic number, because the mean of its divisors is an integer number (3560073827688).
Almost surely, 214240010101311 is an apocalyptic number.
14240010101311 is a deficient number, since it is larger than the sum of its proper divisors (285209441).
14240010101311 is an equidigital number, since it uses as much as digits as its factorization.
14240010101311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 285209440.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 14240010101311 its reverse (11310101004241), we get a palindrome (25550111105552).
The spelling of 14240010101311 in words is "fourteen trillion, two hundred forty billion, ten million, one hundred one thousand, three hundred eleven".
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