Base | Representation |
---|---|
bin | 1100111100111000001100… |
… | …0010011110011011001100 |
3 | 1212102022222010120211002021 |
4 | 3033032003002132123030 |
5 | 3331302022323103234 |
6 | 50141434514335524 |
7 | 2666543563541161 |
oct | 317160302363314 |
9 | 55368863524067 |
10 | 14240015050444 |
11 | 45a017a294507 |
12 | 171b98828a5a4 |
13 | 7c3a9b494c61 |
14 | 373312b18068 |
15 | 19a63732d9b4 |
hex | cf38309e6cc |
14240015050444 has 48 divisors (see below), whose sum is σ = 25703391498400. Its totient is φ = 6899055399936.
The previous prime is 14240015050439. The next prime is 14240015050483. The reversal of 14240015050444 is 44405051004241.
14240015050444 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×142400150504443 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10257892 + ... + 11563060.
Almost surely, 214240015050444 is an apocalyptic number.
It is an amenable number.
14240015050444 is a deficient number, since it is larger than the sum of its proper divisors (11463376447956).
14240015050444 is a wasteful number, since it uses less digits than its factorization.
14240015050444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1305722 (or 1305720 counting only the distinct ones).
The product of its (nonzero) digits is 51200, while the sum is 34.
Adding to 14240015050444 its reverse (44405051004241), we get a palindrome (58645066054685).
The spelling of 14240015050444 in words is "fourteen trillion, two hundred forty billion, fifteen million, fifty thousand, four hundred forty-four".
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