Base | Representation |
---|---|
bin | 100000011000001100100011… |
… | …001111101000101110101011 |
3 | 200200012022220000012121022111 |
4 | 200120030203033220232223 |
5 | 122131041133343003202 |
6 | 1222505432524503151 |
7 | 41665035332462212 |
oct | 4030144317505653 |
9 | 620168800177274 |
10 | 142400232000427 |
11 | 41411665663815 |
12 | 13b7a1516aaab7 |
13 | 615c390692a5b |
14 | 27242caa92079 |
15 | 116e25443d6d7 |
hex | 8183233e8bab |
142400232000427 has 2 divisors, whose sum is σ = 142400232000428. Its totient is φ = 142400232000426.
The previous prime is 142400232000409. The next prime is 142400232000443. The reversal of 142400232000427 is 724000232004241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142400232000427 is a prime.
It is not a weakly prime, because it can be changed into another prime (142400232001427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71200116000213 + 71200116000214.
It is an arithmetic number, because the mean of its divisors is an integer number (71200116000214).
Almost surely, 2142400232000427 is an apocalyptic number.
142400232000427 is a deficient number, since it is larger than the sum of its proper divisors (1).
142400232000427 is an equidigital number, since it uses as much as digits as its factorization.
142400232000427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 31.
Adding to 142400232000427 its reverse (724000232004241), we get a palindrome (866400464004668).
The spelling of 142400232000427 in words is "one hundred forty-two trillion, four hundred billion, two hundred thirty-two million, four hundred twenty-seven", and thus it is an aban number.
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