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1424025506713 is a prime number
BaseRepresentation
bin10100101110001110100…
…010001101001110011001
312001010122210012222210211
4110232032202031032121
5141312401012203323
63010104400411121
7204611452043065
oct24561642151631
95033583188724
101424025506713
114a9a20302067
121abb9b316aa1
13a4392293c34
144cccd3a4aa5
15270974dd70d
hex14b8e88d399

1424025506713 has 2 divisors, whose sum is σ = 1424025506714. Its totient is φ = 1424025506712.

The previous prime is 1424025506699. The next prime is 1424025506737. The reversal of 1424025506713 is 3176055204241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1029356343184 + 394669163529 = 1014572^2 + 628227^2 .

It is an emirp because it is prime and its reverse (3176055204241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1424025506713 - 213 = 1424025498521 is a prime.

It is not a weakly prime, because it can be changed into another prime (1424025506513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712012753356 + 712012753357.

It is an arithmetic number, because the mean of its divisors is an integer number (712012753357).

Almost surely, 21424025506713 is an apocalyptic number.

It is an amenable number.

1424025506713 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424025506713 is an equidigital number, since it uses as much as digits as its factorization.

1424025506713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 40.

The spelling of 1424025506713 in words is "one trillion, four hundred twenty-four billion, twenty-five million, five hundred six thousand, seven hundred thirteen".