Base | Representation |
---|---|
bin | 100000011000001111010100… |
… | …111101010100011010111110 |
3 | 200200012121120210111122221222 |
4 | 200120033110331110122332 |
5 | 122131113240131334402 |
6 | 1222511044433353342 |
7 | 41665202245252361 |
oct | 4030172475243276 |
9 | 620177523448858 |
10 | 142403213543102 |
11 | 41412955667976 |
12 | 13b7a844108852 |
13 | 615c7472b40a5 |
14 | 27244d0a520d8 |
15 | 116e37b0887a2 |
hex | 8183d4f546be |
142403213543102 has 4 divisors (see below), whose sum is σ = 213604820314656. Its totient is φ = 71201606771550.
The previous prime is 142403213543083. The next prime is 142403213543117. The reversal of 142403213543102 is 201345312304241.
142403213543102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35600803385774 + ... + 35600803385777.
It is an arithmetic number, because the mean of its divisors is an integer number (53401205078664).
Almost surely, 2142403213543102 is an apocalyptic number.
142403213543102 is a deficient number, since it is larger than the sum of its proper divisors (71201606771554).
142403213543102 is an equidigital number, since it uses as much as digits as its factorization.
142403213543102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71201606771553.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 142403213543102 its reverse (201345312304241), we get a palindrome (343748525847343).
The spelling of 142403213543102 in words is "one hundred forty-two trillion, four hundred three billion, two hundred thirteen million, five hundred forty-three thousand, one hundred two".
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