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1424112420103 = 3494080551347
BaseRepresentation
bin10100101110010011101…
…101110000010100000111
312001010212211202122120021
4110232103231300110013
5141313040234420403
63010121143320011
7204613555561642
oct24562355602407
95033784678507
101424112420103
114a9a6537540a
121b0004450007
13a43a72a4c89
144ccdab4aa59
152709ee5a8bd
hex14b93b70507

1424112420103 has 4 divisors (see below), whose sum is σ = 1428192971800. Its totient is φ = 1420031868408.

The previous prime is 1424112420091. The next prime is 1424112420109. The reversal of 1424112420103 is 3010242114241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1424112420103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1424112420109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2040275325 + ... + 2040276022.

It is an arithmetic number, because the mean of its divisors is an integer number (357048242950).

Almost surely, 21424112420103 is an apocalyptic number.

1424112420103 is a deficient number, since it is larger than the sum of its proper divisors (4080551697).

1424112420103 is an equidigital number, since it uses as much as digits as its factorization.

1424112420103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4080551696.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1424112420103 its reverse (3010242114241), we get a palindrome (4434354534344).

The spelling of 1424112420103 in words is "one trillion, four hundred twenty-four billion, one hundred twelve million, four hundred twenty thousand, one hundred three".

Divisors: 1 349 4080551347 1424112420103