Search a number
-
+
1424134003049 is a prime number
BaseRepresentation
bin10100101110010101000…
…000000101100101101001
312001010221100101011210122
4110232111000011211221
5141313111301044144
63010123234053025
7204614240202662
oct24562500054551
95033840334718
101424134003049
114a9a76576a5a
121b000b71a175
13a43ab8c0a54
144ccdd968369
15270a1cc07ee
hex14b95005969

1424134003049 has 2 divisors, whose sum is σ = 1424134003050. Its totient is φ = 1424134003048.

The previous prime is 1424134002959. The next prime is 1424134003093. The reversal of 1424134003049 is 9403004314241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 902676708649 + 521457294400 = 950093^2 + 722120^2 .

It is an emirp because it is prime and its reverse (9403004314241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1424134003049 - 212 = 1424133998953 is a prime.

It is not a weakly prime, because it can be changed into another prime (1424134000049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712067001524 + 712067001525.

It is an arithmetic number, because the mean of its divisors is an integer number (712067001525).

Almost surely, 21424134003049 is an apocalyptic number.

It is an amenable number.

1424134003049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424134003049 is an equidigital number, since it uses as much as digits as its factorization.

1424134003049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 35.

The spelling of 1424134003049 in words is "one trillion, four hundred twenty-four billion, one hundred thirty-four million, three thousand, forty-nine".