Base | Representation |
---|---|
bin | 1100111100111101100010… |
… | …0110011100100100101011 |
3 | 1212102110200011201102020011 |
4 | 3033033120212130210223 |
5 | 3331312442314342103 |
6 | 50142233154112351 |
7 | 2666624264200636 |
oct | 317173046344453 |
9 | 55373604642204 |
10 | 14241450543403 |
11 | 45a0846615626 |
12 | 1720108b7b6b7 |
13 | 7c3c699bc985 |
14 | 37340b628c1d |
15 | 19a6bd384d6d |
hex | cf3d899c92b |
14241450543403 has 2 divisors, whose sum is σ = 14241450543404. Its totient is φ = 14241450543402.
The previous prime is 14241450543379. The next prime is 14241450543409. The reversal of 14241450543403 is 30434505414241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14241450543403 - 225 = 14241416988971 is a prime.
It is not a weakly prime, because it can be changed into another prime (14241450543409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120725271701 + 7120725271702.
It is an arithmetic number, because the mean of its divisors is an integer number (7120725271702).
Almost surely, 214241450543403 is an apocalyptic number.
14241450543403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14241450543403 is an equidigital number, since it uses as much as digits as its factorization.
14241450543403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 14241450543403 its reverse (30434505414241), we get a palindrome (44675955957644).
The spelling of 14241450543403 in words is "fourteen trillion, two hundred forty-one billion, four hundred fifty million, five hundred forty-three thousand, four hundred three".
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