1424201123 has 2 divisors, whose sum is σ = 1424201124. Its totient is φ = 1424201122.

The previous prime is 1424201117. The next prime is 1424201131. The reversal of 1424201123 is 3211024241.

It is a weak prime.

It is an emirp because it is prime and its reverse (3211024241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1424201123 is a prime.

It is a super-2 number, since 2×1424201123² = 4056697677508922258, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1424201095 and 1424201104.

It is not a weakly prime, because it can be changed into another prime (1424201113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712100561 + 712100562.

It is an arithmetic number, because the mean of its divisors is an integer number (712100562).

Almost surely, 2^1424201123 is an apocalyptic number.

1424201123 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424201123 is an equidigital number, since it uses as much as digits as its factorization.

1424201123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

The square root of 1424201123 is about 37738.5893085579. The cubic root of 1424201123 is about 1125.0982295792.

Adding to 1424201123 its reverse (3211024241), we get a palindrome (4635225364).

The spelling of 1424201123 in words is "one billion, four hundred twenty-four million, two hundred one thousand, one hundred twenty-three".