142420131200131 has 4 divisors (see below), whose sum is σ = 148612310817552. Its totient is φ = 136227951582712.

The previous prime is 142420131200101. The next prime is 142420131200147. The reversal of 142420131200131 is 131002131024241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142420131200131 - 2⁵ = 142420131200099 is a prime.

It is a super-3 number, since 3×142420131200131³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142420131200096 and 142420131200105.

It is not an unprimeable number, because it can be changed into a prime (142420131200101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3096089808676 + ... + 3096089808721.

It is an arithmetic number, because the mean of its divisors is an integer number (37153077704388).

Almost surely, 2^{142420131200131} is an apocalyptic number.

142420131200131 is a deficient number, since it is larger than the sum of its proper divisors (6192179617421).

142420131200131 is an equidigital number, since it uses as much as digits as its factorization.

142420131200131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6192179617420.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 142420131200131 its reverse (131002131024241), we get a palindrome (273422262224372).

The spelling of 142420131200131 in words is "one hundred forty-two trillion, four hundred twenty billion, one hundred thirty-one million, two hundred thousand, one hundred thirty-one".