Base | Representation |
---|---|
bin | 11101110010010101001111… |
… | …011111000000100101110001 |
3 | 122011211200101202022221221121 |
4 | 131302111033133000211301 |
5 | 114132314331020233431 |
6 | 1142341314223422241 |
7 | 36410406633650251 |
oct | 3562251737004561 |
9 | 564750352287847 |
10 | 131002131024241 |
11 | 38817767821184 |
12 | 12839110754981 |
13 | 58135a91b1ac9 |
14 | 244c773649961 |
15 | 10229ece54611 |
hex | 77254f7c0971 |
131002131024241 has 2 divisors, whose sum is σ = 131002131024242. Its totient is φ = 131002131024240.
The previous prime is 131002131024221. The next prime is 131002131024251. The reversal of 131002131024241 is 142420131200131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108937231290000 + 22064899734241 = 10437300^2 + 4697329^2 .
It is a cyclic number.
It is not a de Polignac number, because 131002131024241 - 223 = 131002122635633 is a prime.
It is not a weakly prime, because it can be changed into another prime (131002131024221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501065512120 + 65501065512121.
It is an arithmetic number, because the mean of its divisors is an integer number (65501065512121).
Almost surely, 2131002131024241 is an apocalyptic number.
It is an amenable number.
131002131024241 is a deficient number, since it is larger than the sum of its proper divisors (1).
131002131024241 is an equidigital number, since it uses as much as digits as its factorization.
131002131024241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 131002131024241 its reverse (142420131200131), we get a palindrome (273422262224372).
The spelling of 131002131024241 in words is "one hundred thirty-one trillion, two billion, one hundred thirty-one million, twenty-four thousand, two hundred forty-one".
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