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1424211433143 = 34111578954741
BaseRepresentation
bin10100101110011001100…
…111011101011010110111
312001011010202002000220220
4110232121213131122313
5141313241111330033
63010135041425423
7204616200303462
oct24563147353267
95034122060826
101424211433143
114aa006252374
121b003163b273
13a43c1961485
144cd09d622d9
15270a89b7bb3
hex14b999dd6b7

1424211433143 has 8 divisors (see below), whose sum is σ = 1945264396656. Its totient is φ = 926316379200.

The previous prime is 1424211433121. The next prime is 1424211433157. The reversal of 1424211433143 is 3413341124241.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1424211433143 - 25 = 1424211433111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1424211433103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5789477248 + ... + 5789477493.

It is an arithmetic number, because the mean of its divisors is an integer number (243158049582).

Almost surely, 21424211433143 is an apocalyptic number.

1424211433143 is a deficient number, since it is larger than the sum of its proper divisors (521052963513).

1424211433143 is a wasteful number, since it uses less digits than its factorization.

1424211433143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11578954785.

The product of its digits is 27648, while the sum is 33.

Adding to 1424211433143 its reverse (3413341124241), we get a palindrome (4837552557384).

The spelling of 1424211433143 in words is "one trillion, four hundred twenty-four billion, two hundred eleven million, four hundred thirty-three thousand, one hundred forty-three".

Divisors: 1 3 41 123 11578954741 34736864223 474737144381 1424211433143