Base | Representation |
---|---|
bin | 100000011000100000110111… |
… | …111110000100001101010011 |
3 | 200200021102012212012002212021 |
4 | 200120200313332010031103 |
5 | 122131420331431134103 |
6 | 1222523442201512311 |
7 | 41666440165221553 |
oct | 4030406776041523 |
9 | 620242185162767 |
10 | 142422054552403 |
11 | 4141a94395003a |
12 | 13b82421aa2697 |
13 | 616145a8255c2 |
14 | 272539b041163 |
15 | 116ead01b9bbd |
hex | 818837f84353 |
142422054552403 has 2 divisors, whose sum is σ = 142422054552404. Its totient is φ = 142422054552402.
The previous prime is 142422054552389. The next prime is 142422054552409. The reversal of 142422054552403 is 304255450224241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142422054552403 - 217 = 142422054421331 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 142422054552403.
It is not a weakly prime, because it can be changed into another prime (142422054552409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71211027276201 + 71211027276202.
It is an arithmetic number, because the mean of its divisors is an integer number (71211027276202).
Almost surely, 2142422054552403 is an apocalyptic number.
142422054552403 is a deficient number, since it is larger than the sum of its proper divisors (1).
142422054552403 is an equidigital number, since it uses as much as digits as its factorization.
142422054552403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536000, while the sum is 43.
The spelling of 142422054552403 in words is "one hundred forty-two trillion, four hundred twenty-two billion, fifty-four million, five hundred fifty-two thousand, four hundred three".
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