Base | Representation |
---|---|
bin | 1100111101000000011101… |
… | …0011111011111001111001 |
3 | 1212102112200210100022121222 |
4 | 3033100013103323321321 |
5 | 3331321043430021103 |
6 | 50142443031041425 |
7 | 2666652561300542 |
oct | 317200723737171 |
9 | 55375623308558 |
10 | 14242234220153 |
11 | 45a1108a17565 |
12 | 17202a7510275 |
13 | 7c4063178b24 |
14 | 3734837454c9 |
15 | 19a717085638 |
hex | cf4074fbe79 |
14242234220153 has 2 divisors, whose sum is σ = 14242234220154. Its totient is φ = 14242234220152.
The previous prime is 14242234220069. The next prime is 14242234220209. The reversal of 14242234220153 is 35102243224241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12230072111104 + 2012162109049 = 3497152^2 + 1418507^2 .
It is a cyclic number.
It is not a de Polignac number, because 14242234220153 - 212 = 14242234216057 is a prime.
It is not a weakly prime, because it can be changed into another prime (14242234220353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121117110076 + 7121117110077.
It is an arithmetic number, because the mean of its divisors is an integer number (7121117110077).
Almost surely, 214242234220153 is an apocalyptic number.
It is an amenable number.
14242234220153 is a deficient number, since it is larger than the sum of its proper divisors (1).
14242234220153 is an equidigital number, since it uses as much as digits as its factorization.
14242234220153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 92160, while the sum is 35.
Adding to 14242234220153 its reverse (35102243224241), we get a palindrome (49344477444394).
The spelling of 14242234220153 in words is "fourteen trillion, two hundred forty-two billion, two hundred thirty-four million, two hundred twenty thousand, one hundred fifty-three".
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