Base | Representation |
---|---|
bin | 100000011000100011000100… |
… | …100011111110100110011011 |
3 | 200200021122022020120221211212 |
4 | 200120203010203332212123 |
5 | 122131440144301114042 |
6 | 1222524512222013335 |
7 | 41666552506236215 |
oct | 4030430443764633 |
9 | 620248266527755 |
10 | 142424413301147 |
11 | 4142094434796a |
12 | 13b8297ba1724b |
13 | 61617453ca013 |
14 | 27255424035b5 |
15 | 116ebbc2e3482 |
hex | 8188c48fe99b |
142424413301147 has 2 divisors, whose sum is σ = 142424413301148. Its totient is φ = 142424413301146.
The previous prime is 142424413301101. The next prime is 142424413301161. The reversal of 142424413301147 is 741103314424241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142424413301147 - 224 = 142424396523931 is a prime.
It is a super-2 number, since 2×1424244133011472 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142424413301197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71212206650573 + 71212206650574.
It is an arithmetic number, because the mean of its divisors is an integer number (71212206650574).
Almost surely, 2142424413301147 is an apocalyptic number.
142424413301147 is a deficient number, since it is larger than the sum of its proper divisors (1).
142424413301147 is an equidigital number, since it uses as much as digits as its factorization.
142424413301147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 258048, while the sum is 41.
Adding to 142424413301147 its reverse (741103314424241), we get a palindrome (883527727725388).
The spelling of 142424413301147 in words is "one hundred forty-two trillion, four hundred twenty-four billion, four hundred thirteen million, three hundred one thousand, one hundred forty-seven".
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