Base | Representation |
---|---|
bin | 10100101110011100001… |
… | …011010111011011001011 |
3 | 12001011020201220222122111 |
4 | 110232130023113123023 |
5 | 141313333111301303 |
6 | 3010143214403151 |
7 | 204620231440045 |
oct | 24563413273313 |
9 | 5034221828574 |
10 | 1424254400203 |
11 | 4aa02852a138 |
12 | 1b0043b004b7 |
13 | a43ca82667b |
14 | 4cd11948a95 |
15 | 270ac653b6d |
hex | 14b9c2d76cb |
1424254400203 has 2 divisors, whose sum is σ = 1424254400204. Its totient is φ = 1424254400202.
The previous prime is 1424254400161. The next prime is 1424254400207. The reversal of 1424254400203 is 3020044524241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1424254400203 is a prime.
It is not a weakly prime, because it can be changed into another prime (1424254400207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712127200101 + 712127200102.
It is an arithmetic number, because the mean of its divisors is an integer number (712127200102).
Almost surely, 21424254400203 is an apocalyptic number.
1424254400203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1424254400203 is an equidigital number, since it uses as much as digits as its factorization.
1424254400203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30720, while the sum is 31.
Adding to 1424254400203 its reverse (3020044524241), we get a palindrome (4444298924444).
The spelling of 1424254400203 in words is "one trillion, four hundred twenty-four billion, two hundred fifty-four million, four hundred thousand, two hundred three".
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