Base | Representation |
---|---|
bin | 1100111101000100100101… |
… | …0111011001010000000010 |
3 | 1212102122120000121212012102 |
4 | 3033101021113121100002 |
5 | 3331330331130014132 |
6 | 50143145015430402 |
7 | 3000022206000005 |
oct | 317211127312002 |
9 | 55378500555172 |
10 | 14243342423042 |
11 | 45a1627524817 |
12 | 1720556685402 |
13 | 7c41ab93c395 |
14 | 37354a9bb53c |
15 | 19a77e4dbc62 |
hex | cf4495d9402 |
14243342423042 has 4 divisors (see below), whose sum is σ = 21365013634566. Its totient is φ = 7121671211520.
The previous prime is 14243342423027. The next prime is 14243342423059. The reversal of 14243342423042 is 24032424334241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 14088469478521 + 154872944521 = 3753461^2 + 393539^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14243342422987 and 14243342423005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3560835605759 + ... + 3560835605762.
Almost surely, 214243342423042 is an apocalyptic number.
14243342423042 is a deficient number, since it is larger than the sum of its proper divisors (7121671211524).
14243342423042 is an equidigital number, since it uses as much as digits as its factorization.
14243342423042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7121671211523.
The product of its (nonzero) digits is 442368, while the sum is 38.
Adding to 14243342423042 its reverse (24032424334241), we get a palindrome (38275766757283).
The spelling of 14243342423042 in words is "fourteen trillion, two hundred forty-three billion, three hundred forty-two million, four hundred twenty-three thousand, forty-two".
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