142441220023 has 4 divisors (see below), whose sum is σ = 149938126360. Its totient is φ = 134944313688.

The previous prime is 142441219957. The next prime is 142441220041. The reversal of 142441220023 is 320022144241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 320022144241 = 9859 ⋅32459899.

It is a cyclic number.

It is not a de Polignac number, because 142441220023 - 2²¹ = 142439122871 is a prime.

It is a super-2 number, since 2×142441220023² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 142441220023.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142441229023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3748453140 + ... + 3748453177.

It is an arithmetic number, because the mean of its divisors is an integer number (37484531590).

Almost surely, 2^142441220023 is an apocalyptic number.

142441220023 is a deficient number, since it is larger than the sum of its proper divisors (7496906337).

142441220023 is an equidigital number, since it uses as much as digits as its factorization.

142441220023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7496906336.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 142441220023 its reverse (320022144241), we get a palindrome (462463364264).

The spelling of 142441220023 in words is "one hundred forty-two billion, four hundred forty-one million, two hundred twenty thousand, twenty-three".