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1424414342017 is a prime number
BaseRepresentation
bin10100101110100101101…
…101011111101110000001
312001011122212212212120101
4110232211231133232001
5141314200032421032
63010211130442401
7204624213064522
oct24564555375601
95034585785511
101424414342017
114aa0aa841857
121b0089593401
13a44249c67b4
144cd28ca0849
15270bb6e8de7
hex14ba5b5fb81

1424414342017 has 2 divisors, whose sum is σ = 1424414342018. Its totient is φ = 1424414342016.

The previous prime is 1424414341939. The next prime is 1424414342041. The reversal of 1424414342017 is 7102434144241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1213337498256 + 211076843761 = 1101516^2 + 459431^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1424414342017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1424414342317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712207171008 + 712207171009.

It is an arithmetic number, because the mean of its divisors is an integer number (712207171009).

Almost surely, 21424414342017 is an apocalyptic number.

It is an amenable number.

1424414342017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1424414342017 is an equidigital number, since it uses as much as digits as its factorization.

1424414342017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86016, while the sum is 37.

Adding to 1424414342017 its reverse (7102434144241), we get a palindrome (8526848486258).

The spelling of 1424414342017 in words is "one trillion, four hundred twenty-four billion, four hundred fourteen million, three hundred forty-two thousand, seventeen".