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14244244433 is a prime number
BaseRepresentation
bin11010100010000010…
…11110101111010001
31100202201001120221122
431101001132233101
5213133011310213
610313235332025
71012662036266
oct152101365721
940681046848
1014244244433
11604a560741
122916451015
1314600b7903
14991ad526d
155857cbd08
hex35105ebd1

14244244433 has 2 divisors, whose sum is σ = 14244244434. Its totient is φ = 14244244432.

The previous prime is 14244244409. The next prime is 14244244439. The reversal of 14244244433 is 33444244241.

14244244433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10817664064 + 3426580369 = 104008^2 + 58537^2 .

It is a cyclic number.

It is not a de Polignac number, because 14244244433 - 28 = 14244244177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14244244393 and 14244244402.

It is not a weakly prime, because it can be changed into another prime (14244244439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122122216 + 7122122217.

It is an arithmetic number, because the mean of its divisors is an integer number (7122122217).

Almost surely, 214244244433 is an apocalyptic number.

It is an amenable number.

14244244433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14244244433 is an equidigital number, since it uses as much as digits as its factorization.

14244244433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 147456, while the sum is 35.

Adding to 14244244433 its reverse (33444244241), we get a palindrome (47688488674).

The spelling of 14244244433 in words is "fourteen billion, two hundred forty-four million, two hundred forty-four thousand, four hundred thirty-three".