Base | Representation |
---|---|
bin | 1000010010101010110… |
… | …0110011111111011110 |
3 | 111121200121101120201102 |
4 | 2010222230303333132 |
5 | 4313214234424014 |
6 | 145235112313102 |
7 | 13202023444355 |
oct | 2045254637736 |
9 | 447617346642 |
10 | 142450311134 |
11 | 5545a53a16a |
12 | 237363a2792 |
13 | 10582414841 |
14 | 6c74c2699c |
15 | 3a8add48de |
hex | 212ab33fde |
142450311134 has 4 divisors (see below), whose sum is σ = 213675466704. Its totient is φ = 71225155566.
The previous prime is 142450311121. The next prime is 142450311151. The reversal of 142450311134 is 431113054241.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1424503111342 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 142450311097 and 142450311106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35612577782 + ... + 35612577785.
It is an arithmetic number, because the mean of its divisors is an integer number (53418866676).
Almost surely, 2142450311134 is an apocalyptic number.
142450311134 is a deficient number, since it is larger than the sum of its proper divisors (71225155570).
142450311134 is an equidigital number, since it uses as much as digits as its factorization.
142450311134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71225155569.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 142450311134 its reverse (431113054241), we get a palindrome (573563365375).
The spelling of 142450311134 in words is "one hundred forty-two billion, four hundred fifty million, three hundred eleven thousand, one hundred thirty-four".
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